If area of a ||gm with sides a and it is A and that of a rectangle with sides a and b is B then

(a) A > B

(b) A = B

(c) A < B

(d) $A \geq B$

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Solution

ANSWER:
(c) A < B
Explanation:
Let h be the height of parallelogram.
Then clearly, h < b
∴ A
= a ⨯ h < a ⨯ b = B
Hence, A < B

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If area of a ||gm with sides a and it is A and that of a rectangle with sides a and b is B then (a) A > B (b) A = B (c) A < B (d) A≥B

ANSWER: (c) A < B Explanation: Let h be the height of parallelogram. Then clearly, h < b ∴ A = a ⨯​ h < a ⨯ b = B Hence, A < B

If area of a ||gm with sides a and it is A and that of a rectangle with sides a and b is B then

(a) A > B

(b) A = B

(c) A < B

(d) $A \geq B$

ANSWER:
(c) A < B
Explanation:
Let h be the height of parallelogram.
Then clearly, h < b
∴ A
= a ⨯ h < a ⨯ b = B
Hence, A < B