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Question

If area of a triangle is 35 sq unit with vertices (2,-6), (5,4) and (k,4), then k is
a) 12
b) -2
c) -12, -2
d) 12, -2

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Solution

Given, 12∣ ∣261541k41∣ ∣=35
i.e. 2(4-4)+6(5-k)+1(20-4k)=70

30-6k +20-4k= 70
On taking positive sign, 10k+50=7010k=20k=2
On taking negative sign, 10k+50=7010k=120k=12
k=12,2. Hence, the correct option is (d).


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