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Question

If (k,2),(2,4) and (3,2) are vertices of the triangle of area 4 square units, then the value of k is/are

A
7
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B
4
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C
1
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D
2
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Solution

The correct option is C 1
Area of triangle = 4 square units
4=12∣ ∣k21241321∣ ∣
4=12|k(42)2(23)+1(412)|
8=|k(2)2(1)+1(8)|2k6=±82k=8+6 or 2k=8+6k=7 or k=1

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