Question

If area of a triangle is $\left(\frac{4x^2+8x+4}{2}\right)$sq.units. Find its base and height

Answer 1

Given area of triangle = $\frac{1}{2}[4x^2+8x+4]$

We know area of triangle = $\frac{1}{2}(base\times height)$

$\Rightarrow \frac{1}{2}(base\times height)=\frac{1}{2}[4x^2+8x+4]$

$\Rightarrow base\times height=4x^2+4x+4x+4$

$\Rightarrow base\times height$ =4x(x+1)+4(x+1)

$\Rightarrow base\times height=(4x+4)(x+1)$

on comparing we get base = 4x+4

and height = x+1