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Question

If at 298 K the bond energies of C - H, C - C, C=C and H - H bonds are respectively 414, 347, 615 and 435 kJ mol1, the value of enthalpy change for the reaction
CH2=CH2(g)+H2(g)CH3CH3 is:


A

-250 kJ

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B

+125 kJ

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C

-125 kJ

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D

+250 kJ

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Solution

The correct option is C

-125 kJ


CH2=CH2(g)+H2(g)CH3CH3Enthalpy change = Bond energy of raeactants -Bond energy of products.ΔH=1(C=C)+4(CH)+1(HH)1(CC)6(CH)=1(C=C)+1(HH)1(CC)2(CH)=615+4353472×414=10501175=125kJ.


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