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Ionic Compounds and Radius Ratios

If atom A ide...

Question

If atom A ideally fit in tetrahedral voids formed by atoms of B of radius r then the minimum distance between centers of A and B will be:

A

0.225r

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B

0.414r

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C

1.225r

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D

1.414r

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Solution

The correct option is C 1.225r

$\frac{r_{A}}{r_{B}} = 0.225$ for tetrahedral void

$r_{A} + r_{B} = 0.225 r_{B} + r_{B} = 1.225 r_{B}$

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