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Faraday's First Law

If atomic wei...

Question

If atomic weight of a metal is $60$ and its equivalent weight is $20$ . Then its phosphate formula will be:

A

M_{5} (P O_{4})_{2}

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B

M P O_{4}

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C

M_{2} (P O_{4})_{3}

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D

M (P O_{4})_{2}

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Solution

The correct option is B $M P O_{4}$
Valency $= \frac{60}{20} = 3$
Therefore, its phosphate formula will be $M P O_{4}$

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