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Question

If ax2+bx+c,a,b,cϵR, a < 0 has no real zeros and a - b+c<0,  then the 

value of ac



A

> 0

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B

< 0        

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C

= 0        

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D

< -1

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Solution

The correct option is A

> 0


f(X)  = ax2+bx+c 

f(-1) = a - b + c < 0 a < 0

f(0) = 0 + 0 + c < 0

ac > 0  


Mathematics

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