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Question

If f(x)= a x square plus b x plus c has no real zeros and a+b+c <0 , then
A) c=0
B) c>0
C) c<0
D) none of these

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Solution

Since f(x)≠0 for x∈R, either f(x)>0 for all x∈R or f(x)<0 for all x∈R by continuity of f.

Since f(1)=a+b+c<0, we conclude that f(x)<0 for all x∈R. Therefore f(0)=c<0.


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