Question

If $\left[\begin{array}{ccc}1& 0& 0\\ 0& 0& 1\\ 0& 1& 0\end{array}\right]\left[\begin{array}{c}x\\ y\\ z\end{array}\right]=\left[\begin{array}{c}2\\ -1\\ 3\end{array}\right]$, find $x,y,z$

Answer 1

Given,

$\left[\begin{array}{ccc}1& 0& 0\\ 0& 0& 1\\ 0& 1& 0\end{array}\right]\left[\begin{array}{c}x\\ y\\ z\end{array}\right]=\left[\begin{array}{c}2\\ -1\\ 3\end{array}\right]$

upon performing multiplication operation, we get,

$\left[\begin{array}{c}x\\ z\\ y\end{array}\right]=\left[\begin{array}{c}2\\ -1\\ 3\end{array}\right]$

equating LHS and RHS, we get,

$x=2,y=3,z=-1$