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Question

If (3x+75y+12−3x)=(1y−288), then the value of x and y respectively are

A
2,7
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B
13,7
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C
13,23
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D
2,7
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Solution

The correct option is A 2,7
Given, (3x+75y+123x)=(1y288)
Therefore, 3x+7=1
3x=6
x=2
Also, y+1=8
y=81
y=7
Thus, the value of x and y are 2 and 7 respectively.

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