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Question

If [3x+75y+12−3x]=[1y−288], then the values of x and y respectively are

A
2,7
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B
13,7
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C
13,23
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D
2,7
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Solution

The correct option is A 2,7
[3x+75y+123x]=[1y288]
Comparing both sides corresponding columns of both sides.
3x+7=1 & y2=5
3x=6, y=7
x=2, y=7
Hence, the answer is 2,7.

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