If Cdiamond- Cgraphite- - H - -ve- This means -

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Heat of Formation

If Cdiamond...

Question

If $C_{d i a m o n d} ⟶ C_{g r a p h i t e}; Δ H = - v e$ . This means :

Graphite is more stable form than diamond.

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Graphite has more energy than diamond.

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Both are equally stable form.

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Stability of form cannot be predicted by

Δ H

values.

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Solution

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Similar questions

Assertion- $C (g r a p h i t e) + O_{2 (g)} \to C O_{2 (g)}$ ,

$Δ H = - 393.5 k . J$

$C (d i a m o n d) + O_{2 (g)} \to C O_{2 (g)}$ ,

$Δ H = - 395.4 k . J$

Reason(R): graphite is more stable than diamond, so heat of combustion is less.

C_{d i a m o n d} \to C_{g r a p h i t e}; Δ H = - v e

C_{d i a m o n d} \to C_{g r a p h i t e}; Δ H = - v e .

C H_{3} - C H_{2} - C D_{2}^{+}

C H_{3} - C H_{2} - C T_{2}^{+}

C (g r a p h i t e) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 393.7 k J

C (d i a m o n d) ⟶ C (g r a p h i t e); Δ H = - 2.1 k J

Δ H

C O_{2}

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