Question

If $C$ is the capacity, $V$ is the potential difference, the energy stored in a capacitor is given by $E=\frac{1}{2}{CV}^2$. The dimension of time in ${CV}^2$ is:

• A. $-2$
• B. $2$
• C. $1$
• D. $-1$

Answer 1

The correct option is A $-2$

As we know energy stored inside the capacitor is $\frac{1}{2}c{v}^2$.
${cv}^2$ will have dimensions of energy only, i.e.,$M{L}^2{T}^{-2}$
Hence, option A is correct.