If C r stands for nCr - then the value of 2C0 - 222C1 - 233C2 -1n-12n-1n-1 is equal to

The correct option is B 0 if n is odd C_ 0 + 2^ 2 C_ 1 / 2 + 2^ 3 C_ 2 / 3 + 2^ 4 C_ 3 / 4 +.......( 1 ) 2^ n+1 C_ n / n+1 =( 1 ) 1^ n ...

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Combination

If C r stand...

Question

If C $_{r}$ stands for $^{n} C_{r}$ , then the value of $2 C_{0} - \frac{2^{2}}{2} C_{1} + \frac{2^{3}}{3} C_{2} + . . . . . + (- 1)^{n + 1} \frac{2^{n + 1}}{(n + 1)}$ is equal to

0

if n is even

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0

if n is odd

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\frac{1}{n + 1}

, if n is even

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\frac{1}{n + 1}

, if n is odd

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a = - 1, b = 0

a = 1, b = 0

a = - 1, b = 0

3

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- \frac{1}{n}

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c_{0}, c_{1}, c_{2}, . . . . . . c_{n}

(1 + x)^{n}

n

c_{0} - c_{1} + c_{2} - c_{3} + . . . . . . . + (- 1)^{r} c_{r} = (- 1)^{r} \frac{| n - 1 - ---- -}{| r - | n - r - 1 - -------- -}

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(- 1)^{\frac{n}{2}} c_{\frac{n}{2}},

n

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