If -132-2-23-4- then find the value of -3-

𝑥=1(32)^ 2×(23)^ 4 ⇒ 𝑥=1(32)^ 2×(32)^4 =1(32)^ 2+4 ⇒ 𝑥=1(32)^ 2×(32)^4 ⇒ 𝑥=1(32)^ 2+4 nbsp; ⇒ 𝑥=1(32)^2=(23)^2 nbsp; ⇒ 𝑥^ 3=[(23)^2]^ 3=(23)^ 6 nbsp; nb ...

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Byju's Answer

Standard XII

Mathematics

Parametric Differentiation

If 𝑥=132-2×2...

Question

If $x = \frac{1}{{(\frac{3}{2})}^{- 2} \times {(\frac{2}{3})}^{- 4}}$ , then find the value of $x^{- 3}$ .

{(\frac{3}{2})}^{8}

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{(\frac{2}{3})}^{10}

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{(\frac{3}{2})}^{- 12}

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{(\frac{2}{3})}^{- 6}

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Solution

The correct option is D ${(\frac{2}{3})}^{- 6}$
$x = \frac{1}{{(\frac{3}{2})}^{- 2} \times {(\frac{2}{3})}^{- 4}}$
$\Rightarrow x = \frac{1}{{(\frac{3}{2})}^{- 2} \times {(\frac{3}{2})}^{4}}$
$\Rightarrow x = \frac{1}{{(\frac{3}{2})}^{- 2 + 4}}$
$\Rightarrow x = \frac{1}{{(\frac{3}{2})}^{- 2} \times {(\frac{3}{2})}^{4}}$
$\Rightarrow x = \frac{1}{{(\frac{3}{2})}^{- 2 + 4}}$
$\Rightarrow x = \frac{1}{{(\frac{3}{2})}^{2}} = {(\frac{2}{3})}^{2}$
$\Rightarrow x^{- 3} = {[{(\frac{2}{3})}^{2}]}^{- 3} = {(\frac{2}{3})}^{- 6}$

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If x=1(32)−2×(23)−4, then find the value of x−3.

The correct option is D (23)−6x=1(32)−2×(23)−4 ⇒x=1(32)−2×(32)4 ⇒x=1(32)−2+4 ⇒x=1(32)−2×(32)4 ⇒x=1(32)−2+4 ⇒x=1(32)2=(23)2 ⇒x−3=[(23)2]−3=(23)−6

If $x = \frac{1}{{(\frac{3}{2})}^{- 2} \times {(\frac{2}{3})}^{- 4}}$ , then find the value of $x^{- 3}$ .