If x3+1=715, then x=−m5. So, the value of m is
Expand: (1)(a+2)(a−1)(2) (m−4)(m+6)(3) (p+8)(p−3)(4) (13+x)(13−x)(5) (3x+4y)(3x+5y)(6) (9x−5t)(9x+3t)(7) (m+23)(m−73)(8) (x+1x)(x−1x)(9) (1y+4)(1y−9)
Simplify:
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