Question

If $C{H}_{3}COOH+O{H}^{-}\to C{H}_{3}CO{O}^{-}+H_{2}O+q_1$

$H^{+}+O{H}^{-}\to H_{2}O+q_2$

then the enthalpy change for the reaction $C{H}_{3}COOH\to C{H}_{3}CO{O}^{-}+H^{+}$ is equal to:

• A. $(q_1+q_2)$
• B. $(q_1-q_2)$
• C. $(q_2-q_1)$
• D. $(-q_1-q_2)$

Answer 1

The correct option is C $(q_2-q_1)$

1) $C{H}_{3}COOH+O{H}^{-}\to CHCO{O}^{-}+H_{2}O\Delta H=-q_1$

$H^{+}+O{H}^{-}\to H_{2}O\Delta H=-q_2$

2) $H_{2}O\to H^{+}+O{H}^{-}\Delta H=+q_2$

Adding 1 & 2

$C{H}_{3}COOH\to CHCO{O}^{-}+H^{+}\Delta H=-q_1+q_2$
Therefore enthalpy change for reaction $=q_2-q_1$

Option C is correct.