The correct option is
B maximum
The magnitude of the induced emf in a circuit is proportional to the time rate of magnetic flux linked with the circuit.
Consider a rectangular loop which rotates in a uniform magnetic field, around an axis in the plane of the loop and passing through the centres of opposite sides.
If the area of the loop is A and the field strength is B and the normal to the loop makes an angle phi with the field direction at any instant, the flux through the loop at any time is B A cos phi. The flux is a maximum when the loop is normal to the field (ϕ=0) and zero when the loop is aligned parallel to the field (ϕ=90).
If the loop rotates with angular velocity w, then we can substitute phi = wt, and we can then write flux at any instant =ABcoswt.
The induced emf is E=−d(ABcoswt)dt
E=ABwsinwt.
The answer to your question follows from that last expression. The induced emf is a sinusoidal function. It will be a minimum (that is zero), when phi = wt = 0, when the plane of the coil is normal to the field, and it will be maximum when ϕ=wt=90, or when the plane of the loop is parallel to the field