If cos B-1- find the value of B if 0 - B - 90A- 60B- 45C- 90D- 0

The correct option is D 0 B lies in this range 0^o A+B ≤ 90^o cos B = 1 ⇒ cos B = cos 90 ⇒ B=0 ...

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Standard Values

If cos B=1, f...

Question

If cos B = 1, find the value of B if $0 \leq B \leq 90$ .

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If sin B = 1, find the value of B if $0 \leq B \leq 90$ .

$z_{1}$ (3, 2), $z_{2}$ (1, 5) and origin O form a triangle. Find the angle between the sides O $z_{1}$ and O $z_{2}$

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cos B = \frac{4}{5}

sin (A + B)

\frac{cos A}{3} = \frac{cos B}{4} = \frac{1}{5}, - \frac{π}{2} < A < 0, - \frac{π}{2} < B < 0

2 sin A + 4 sin B

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cos A + cos B + cos C = 0

sin (\frac{A - B}{2})

(where A, B, C \in [0, 2 π])

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