If cos - - - 4 5 -sin - - - 5 13 and - - lie between 0 and - 4- then find tan 2-

cos (α+β)=45 sin(α β)=513 sin(α+β)=35 α β=sin^ 1(513) and α +β =sin^ 135 Therefore, 2α=sin^ 1(513)+sin^ 1(35) sin 2α =5665 ...

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Inequality

If cos α +β...

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If $cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13} a n d α, β$ lie between $0$ and $\frac{π}{4}$ ; then find $tan 2 α$ .

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cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13} and α, β

0

\frac{π}{4},

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cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

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0 < α, β < \frac{π}{4}, cos (α + β) = \frac{4}{5}, sin (α - β) = \frac{5}{13}

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