If cos-23- find the value of -1 -1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Value of Standard Angle(30,60,90)

If cosθ=23, f...

Question

If $\cos θ = \frac{2}{3}$ , find the value of $\frac{\sec θ - 1}{\sec θ + 1}$ .

Open in App

Solution

Suggest Corrections

Similar questions

If \cos θ = \frac{2}{3}, then write the value of \frac{(\sec θ - 1)}{(\sec θ + 1)} .

\sqrt{\frac{\sec θ - 1}{\sec θ + 1}} + \sqrt{\frac{\sec θ + 1}{\sec θ - 1}} = 2 cosec θ

\sqrt{\frac{1 + \sin θ}{1 - \sin θ}} + \sqrt{\frac{1 - \sin θ}{1 + \sin θ}} = 2 \sec θ

\sqrt{\frac{1 + \cos θ}{1 - \cos θ}} + \sqrt{\frac{1 - \cos θ}{1 + \cos θ}} = 2 cosec θ

\frac{\sec θ - 1}{\sec θ + 1} = {(\frac{\sin θ}{1 + \cos θ})}^{2}

\frac{\sin θ + 1 - \cos θ}{\cos θ - 1 + \sin θ} = \frac{1 + \sin θ}{\cos θ}

\frac{\sin θ - \cos θ + 1}{\sin θ + \cos θ - 1} = \frac{1}{s e c θ - \tan θ}

\frac{sec θ - 1}{sec θ + 1} = \frac{1 - cos θ}{1 + cos θ}

\frac{sinθ - cosθ + 1}{sinθ + cosθ - 1} = \frac{1}{(secθ - tanθ)} .

\frac{secθ cosec (90 ° - θ) - \tan θ \cot (90 ° - θ) + \sin^{2} 65 ° + \sin^{2} 25 °}{\tan 10 ° \tan 20 ° \tan 60 ° \tan 70 ° \tan 80 °}

Join BYJU'S Learning Program