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Question

If cosx=35 where x(3π2,2π), then the value of sin4x is 
  1. 336625
  2. 144625
  3. 224625
  4. 336475


Solution

The correct option is A 336625
cosx=35
As x(3π2,2π)
sinx=45

Now,
sin4x=2sin2xcos2x=4sinxcosxcos2x=4sinxcosx(2cos2x1)=4×(45)×35[2(35)21]=4825×[18251]=4825×725=336625

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