If cos2θ=a then cos3θcosθ equals to
2a+1
2a-1
2a-2
2a+2
cos3θcosθ=4cos3θ−3cosθcosθ
= 4 cos2θ−3
= 2 (1+cos2θ)−3
= 2(1+a) - 3
= 2a - 1
If sin θ + cos θ = a, cos θ - sin θ = b, then sin θ (sin θ - cos θ ) + sin2θ(sin2θ−cos2θ)+sin3θ(sin3θ−cos3θ)+ . . .. . is equal to