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Question

If (cot1x)23(cot1x)+2>0, then x lies in


  1. (cot1,)

  2. (,cot1)(cot2,)

  3. (,cot2)(cot1,)

  4. (cot2,cot1)


Solution

The correct option is C

(,cot2)(cot1,)


(cot1x1)(cot1x2)>0
x<cot2 or x>cot1
(cot1x is  a decreasing function)

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