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Byju's Answer
Standard XII
Mathematics
Parametric Differentiation
If θ-1 θ+1=1-...
Question
If
cot
θ
-
1
cot
θ
+
1
=
1
-
3
1
+
3
then find the acute angle θ.
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Solution
Given
:
cot
θ
-
1
cot
θ
+
1
=
1
-
3
1
+
3
cot
θ
-
1
cot
θ
+
1
=
1
-
3
1
+
3
⇒
1
tan
θ
-
1
1
tan
θ
+
1
=
1
-
3
1
+
3
∵
cot
θ
=
1
tan
θ
⇒
1
-
tan
θ
tan
θ
1
+
tan
θ
tan
θ
=
1
-
3
1
+
3
⇒
1
-
tan
θ
1
+
tan
θ
=
1
-
3
1
+
3
On
comparing
LHS
and
RHS
,
we
get
tan
θ
=
3
⇒
θ
=
60
°
∵
tan
60
°
=
3
Hence
,
the
acute
angle
θ
is
equal
to
60
°
.
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