Question

If $cot\Theta =1$; find the value of :
$5ta{n}^2\Theta +2si{n}^2\Theta -3$

Answer 1

$\cot \Theta =1$
$\cot \Theta =\cot 45$
$\Theta ={45}^{\circ }$
Now, $5ta{n}^2\Theta +2si{n}^2\Theta -3$
= $5ta{n}^{2}45+2si{n}^{2}45-3$
= $5(1{)}^2+2(\frac{1}{\sqrt{2}}{)}^2-3$
= $5+1-3$
= $3$