Question

If current is given by $I=I_0\cos \omega t+I_0\sin \omega t$. The RMS value of current is given by:

• A. $\sqrt{\frac{I_0}{2}}$
• B. $\frac{I_0}{\sqrt{2}}$
• C. $\frac{I_0}{2}$
• D. $I_0$

Answer 1

The correct option is D $I_0$

I=$I_{0}cos\omega t+l_{0}sin\omega t$

I=$I_0\sqrt{2}sin(\omega t+{45}^0)$

$I_{peak}=I_0\sqrt{2}$

$I_{rms}=\frac{I_{peak}}{\sqrt{2}}=I_0$