If Δ1,Δ2 are areas of incircle and circumcircle of a triangle with sides 3,4 and 5 then Δ1Δ2=
A
1625
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B
425
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C
925
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D
916
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Solution
The correct option is B425 sidesoftriangle3,4,5 as32+42=52 Henceitisarightangledtriangle asinA=2R ⇒a=2R R=a2=52 r=Δs=12×4×35+4+32=1 Thus area of inscribed circle s1area of circumscribed circle s2=πr2πR2=12(52)2=425