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Nernst Equation

If Δ G = Δ ...

Question

If $Δ G = Δ H - T Δ S$ and $Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{P}$ then variation of EMF of a cell E, with temperature T, is given by:

\frac{Δ H}{n F}

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\frac{Δ G}{n F}

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\frac{Δ S}{n F}

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- \frac{Δ S}{n F}

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Solution

The correct option is C $\frac{Δ S}{n F}$
On comparison:
$Δ S = - [\frac{d (Δ G)}{d T}]$
$Δ S = - \frac{d (- n F E)}{d T} = n F (\begin{matrix} \frac{d E}{d T} \end{matrix}) [H e r e E i s t h e E_{m f} o f c e l l]$
$∴ \frac{d E}{d T} = \frac{Δ S}{n F}$

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Similar questions

Δ G = Δ H - T Δ S

Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}

$Δ G = Δ H - T Δ S$ and $Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}$ , then $(\frac{d E_{c e l l}}{d T})$ is:

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

Δ S

d (Δ G) = - (Δ S_{reaction}) . d T

Δ G = Δ H - T Δ S

Δ G = Δ H + T {(\frac{d (Δ G)}{d T})}_{P}

{(\frac{d E}{d T})}_{P}

(E_{c e l l})

Δ G = n F E_{c e l l}

Δ G

d (Δ G) = (Δ V) d p - (Δ S) d T

d (Δ G) = - (Δ S) d T

Δ G = Δ H - T Δ S

∴ Δ G = Δ H + T {(\frac{d (Δ G)}{Δ T})}_{P}

{(\frac{d E_{c e l l}}{d T})}_{p}

{(\frac{d E}{d T})}_{p}

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