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Question

If 112x+x2=1+b1X+b2x2+b3x3+
Then coefficient of b1?

A
3
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B
2
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C
4
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D
1
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Solution

The correct option is C 2
Given, 112x+x2 =1(1x)2
=(1x)2
=1(2)x+(2)(21)x22!...(1)nxnk!(n)(n1)(n2)...(n(k1)!...
Hence b1=2

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