Question

If $\frac{1}{3}$ of a number exceeds its $\frac{2}{7}$ by 1, find the number.

Answer 1

Let the number be $x$.

According to the question,

$\frac{x}{3}=\frac{2x}{7}+1$

$\frac{x}{3}=\frac{2x+7}{7}$

$7x=6x+21$

$x=21$

Hence, this is the answer.