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Question

If 3x+4x23x+2=Ax2Bx1, then A +B =

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Solution

3x+4x23x+2=3x+4(x2)(x1)=Ax2Bx1
3x+4(x2)(x1)=A(x1)B(x2)(x2)(x1)
3x+4=AxABx+2B
=(AB)x+(2BA)
AB=3(1)
and 2BA=4(2)
_____________________
B=7 and A7=3A=7+3=10
(A,B)=(10,7)

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