Question

If $\frac{4}{5},a,2$ are three consecutive terms of an $A.P.$ then find the value of ${}^{\prime }{a}^{\prime }$.

Answer 1

Since, $\frac{4}{5},a,2$ are in A.P.

$a-\frac{4}{5}=2-a$

$5a-4=10-5a$

$10a=14$

$a=\frac{7}{5}$