Question

If $\frac{4+z-(3+2z)}{6}=\frac{-z-3(5-2)}{7}$, then the value of $z$ will be

• A. $-61$
• B. $-\frac{61}{27}$
• C. $\frac{61}{27}$
• D. $61$

Answer 1

The correct option is D $61$

Begin by combining like terms on both sides of the equation.
$\frac{4+z-(3+2z)}{6}=\frac{-z-3(5-2)}{7}$

$\Rightarrow \frac{1-z}{6}=\frac{-z-9}{7}$

$\Rightarrow 7-7z=-6z-54$

$\Rightarrow -z=-61$

$\Rightarrow z=61$