If x3-3x3x2-1-18961 then find the value of x-

We have, x^3 + 3x/3x^2 + 1 = 189/61 61( x^ 3 +3x ) =189( 3 x^ 2 +1 ) #160; 61 x^ 3 +183x=567 x^ 2 +189 61 x^ 3 567 x^ 2 +183x 189=0 ...

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Complex Numbers

If x3+3x3x2...

Question

If $\frac{x^{3} + 3 x}{3 x^{2} + 1} = \frac{189}{61}$ then find the value of $x$ ?

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Solution

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