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Question

If $$\dfrac{x}{y}+\dfrac{y}{x}=-1, (x, y \neq 0)$$, then value of $$x^3-y^3$$ is:


A
1
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B
1
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C
0
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D
None of these
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Solution

The correct option is D $$0$$
if $$\dfrac{x}{y} +\dfrac{y}{x}=-1$$
simplifies to $$x^2+xy+y^2=0$$
as $$(x^3-y^3)=(x-y)(x^2+xy+y^2)=0$$   using above result

Mathematics

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