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Question

If dimensions of critical velocity vc of a liquid flowing through a tube are expressed as [ηxpyrz], where η,p and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then values of x,y and z are given by:

A
1,1,1
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B
1, -1, -1
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C
-1, -1, 1
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D
-1, -1, -1
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Solution

The correct option is D 1, -1, -1
[v]=[LT1]
η=FAdvdx

[η]=[MLT2][L2][T1]=[M1L1T1]

[ρ]=[ML3]

[LT1]=[M1L1T1]x[ML3]y[L]z

Equating the exponents of M, L and T on both LHS and RHS$
M0=M(x+y)
y=x
For T,
1=x
x = 1
y=x=1
For L
1=x3y+z1+3+z
1=2+zz=1
z=1

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