CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If direction cosines of a vector of magnitude 3 are 23,13,23 and a>0, then vector is ____

A
2i+j+2k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2ij+2k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
i2j+2k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
i+2j+2k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2ij+2k
Unit vector with direction cosine 23,13,23 is given by
^a=23^i13^j+23^k

Thus vector with magnitude 3 and direction cosine as above is given by
3^a=2^i^j+2^k

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Direction Cosines and Direction Ratios
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon