If direction cosines of a vector of magnitude 3 are 2-3-9-3- 2-3 and a -0 then vector isA- i -2 j -2 kB- Question is incorrect C- 2 i - j -2 kD- 2 i - j -0 k

The correct option is B Question is incorrect Question wrong. Grace marks would be given. ...

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Direction Cosines

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If direction cosines of a vector of magnitude 3 are $\frac{2}{3}, - \frac{9}{3}, \frac{2}{3}$ and a > 0 then vector is____________

2i + j + 0k

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2i - j + 2k

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i – 2j + 2k

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Question is incorrect

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If direction cosines of a vector of magnitude 3 are $\frac{2}{3}, - \frac{9}{3}, \frac{2}{3}$ and a > 0 then vector is____________

3

\frac{2}{3}, \frac{- 1}{3}, \frac{2}{3}

a > 0

3

\frac{2}{3}, - \frac{1}{3}, \frac{2}{3}

a > 0

3

\frac{2}{3}, \frac{- a}{3}, \frac{2}{3}, a > 0

a = 2 i - j + k, b = i + 2 j - k

c = i + j - 2 k

b

c

a

\sqrt{\frac{2}{3}}

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