Question

If $0^0<A<{90}^0$ and $\sin A=\frac{4}{5}$, then find the value of $\tan A+\sec A$.

Answer 1

Because $\sin A=\frac{4}{5}$ so $\tan A=\frac{4}{3}$ and $\sec A=\frac{5}{3}$
$\therefore \tan A+\sec A=\frac{5}{3}+\frac{4}{3}=\frac{9}{3}=3$