If a1,a2,a3... are positive numbers in GP then logan,logan+1,logan+2 are in
A
AP
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B
GP
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C
HP
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D
none of these
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Solution
The correct option is AAP Since, a1,a2,a3,.... are in G.P. Let a and r be the first term and common ratio respectively ⇒logan=loga+nlogr ...(1) logan+1=loga+(n+1)logr ...(2) and logan+2=loga+(n+2)logr ...(3) From (1), (2) and (3) 2logan+1=logan+logan+2 Therefore, logan,logan+1,logan+2 are in A.P. Ans: A