Question

If $a=\sqrt{11}+\sqrt{3},b=\sqrt{12}+\sqrt{2}$ and $c=\sqrt{17}-\sqrt{3}$ then arrange them in descending order

• A. $a<b<c$
• B. $a>b<c$
• C. $a=b=c$
• D. $a>b>c$

Answer 1

Answer: (D)

$a>b>c$

Let us first write the values of $a,b$ and $c$ as shown below:

$a=\sqrt{11}+\sqrt{3}=3.317+1.732=5.049b=\sqrt{12}+\sqrt{2}=3.464+1.414=4.878c=\sqrt{17}-\sqrt{3}=4.123-1.732=2.391$

Since, $5.049>4.878>2.391$, therefore, $a>b>c$

And we also know that numbers are said to be in descending order when they are arranged from the largest to the smallest number.

Hence, the descending order of $a,b$ and $c$ is $a>b>c$