Question

In Δ ABC, ∠B = 35°, ∠C = 65° and the bisector of ∠BAC meets BC in P. Arrange AP, BP and CP in descending order.

Answer 1

It is given that

AP is the bisector of

We have to arrange, and in descending order.

In we have

(As AP is the bisector of)

So (Sides in front or greater angle will be greater) ........(1)

In we have

(As AP is the bisector of)

Since,

So ..........(2)

Hence

From (1) & (2) we have