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Question

If [2x30y−1]=[x−3302], then the values of x and y respectively are

A
3,3
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B
3,3
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C
3,3
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D
3,3
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Solution

The correct option is C 3,3
Given [2x30y1]=[x3302]
Equating corresponding elements, we get
2x=x3x=3 and
y1=2y=3

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