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B
2
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C
4
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D
8
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Solution
The correct options are A 3 D 4 Taking cot on both the sides, the inequality reverses. n2−10n+21.6<√3π (n−5)2−25+21.6<√3π (n−5)2<3.4+√3π −√3.4+√3π<n−5<√3.4+√3π 5−√3.4+√3π<n<5+√3.4+√3π 2.02<n<7.97 However nϵN Hence the possible values of n are 3,4,5,6,7.