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Question

If 3+2isinθ12isinθ is a real number and 0<θ<2π then θ=

A
π
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B
π2
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C
π3
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D
π6
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Solution

The correct option is A π
after rationalization , the given number is
(34sin2θ)+8isinθ1+4sin2θ
for real, imaginary part is zero
so sinθ=0
so θ=π

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