Question

If $\frac{x}{y}=\frac{13}{6}$, then the value of $\frac{2x^2+5y^2}{2x^2-5y^2}$ is $\frac{259}{79}$.
If true, then enter $1$ else, enter $0$.

Answer 1

Given $\frac{x}{y}=\frac{13}{6}$,

Let $x=13a,y=6a$

$\therefore \frac{2x^2+5y^2}{2x^2\times 5y^2}$

$=\frac{2(13a{)}^2+5(6a{)}^2}{2(13a{)}^2\times 5(6a{)}^2}$

$=\frac{518a^2}{158a^2}$

$=\frac{259}{79}$