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Byju's Answer
Standard XII
Mathematics
Higher Order Derivatives
If ∫√x+x√x+x ...
Question
If
∫
(
√
x
+
x
√
x
+
x
)
d
x
=
x
a
a
+
x
b
b
+
x
c
c
+
K
such that
x
>
0
,
then the value of
8
a
b
c
is
(where
K
is constant of integration and
a
,
b
and
c
are fixed constants)
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Solution
∫
(
√
x
+
x
√
x
+
x
)
d
x
=
∫
√
x
d
x
+
∫
x
√
x
d
x
+
∫
x
d
x
=
x
3
/
2
3
2
+
x
3
/
2
+
1
3
2
+
1
+
x
2
2
+
K
⇒
x
a
a
+
x
b
b
+
x
c
c
+
K
=
x
3
/
2
3
2
+
x
3
/
2
+
1
3
2
+
1
+
x
2
2
+
K
By comparing, we get
a
=
3
2
,
b
=
5
2
,
c
=
2
∴
8
a
b
c
=
8
×
3
2
×
5
2
×
2
=
60
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0
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If
∫
(
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+
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+
2
)
d
x
=
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is constant of integration)
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√
x
+
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If
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x
+
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x
)
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sin
2
x
+
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x
)
d
x
=
A
sin
x
+
B
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x
+
C
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(
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A
+
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−
C
is equal to
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A
,
B
,
C
are fixed constants and
K
is constant of integration)
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If
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−
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x
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+
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2
+
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x
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∣
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−
x
+
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x
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∣
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is (where
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is fixed constant and
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is integration constant)
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Standard XII Mathematics
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