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Question

If logba+logca+logab+logac+logbc+logcb=3 (where a,b,c are different positive real numbers 1 ), then find the value of abc

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Solution

(loga)2logblogc+(logb)2logalogc+(logc)2logalogb=3
(loga)3+(logb)3+(logc)33logalogblogc=0
loga+logb+logc=0(asa,b.c,aredistinct)
logabc=0
abc=1
Ans: 1

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